AME 514 - Special topics in
combustion - Fall 2008
Assignment #4
Due: Monday 12/1/08, 4:30 pm
in my office (OHE 430J)
Since theyÕre werenÕt many references in this set
of lectures, IÕve decided to skip Part I.
Part 2 will count twice as much as did for the other homework sets. YouÕll notice Part 2 is somewhat more
time consuming than usual, though probably not twice as long as the
others. (I think all the words in
this problem set that make it look like a long problem set make it easier to
do, not more difficult, since IÕve give you step by step instructions. Of course, your mileage may vary).
Problem #1
a.
Show that for heat
addition at constant temperature
(which really simplifies things) using the first law (h1 + u12/2
+ q = h2 + u22/2), the entropy of an ideal gas
(s2-s1 = CPln(T2/T1) –
Rln(P2/P1)), the enthalpy of an ideal gas (h2 –
h1 = CP(T2 – T1)), the
definition of Mach number (M = u/c = u/(gRT)1/2) and the consequence of second law (ds = dq/T):
P2/P1 = exp[(g/2)(M12- M22)]
(yes you already have this result from the lecture
notes but IÕd like for you to show itÉ)
b.
By additionally
using mass conservation, show that
A2/A1 = (M1/M2)exp[(g/2)(M22- M12)]
(ditto comment in part a)
c.
Now consider a
propulsion system based on this.
First the air will be decelerated isentropically (not to M = 0) then
heat will be added at constant temperature. For a flight Mach number of 15, an ambient atmosphere at
100,000 feet (227K and 0.0107 atm, with g = 1.4), to what Mach number could the air be decelerated if the
maximum allowable gas temperature is 3000K? What would the corresponding pressure be?
d.
From this condition,
if heat is added at constant temperature until the ambient pressure was reached
(not a good way to operate, but this represents a sort of maximum heat
addition), what would the exit Mach (Me) number be? What would the area ratio be?
e.
What would the
specific thrust be? (Note for this
case specific thrust = Thrust/
c1 =
(ue –
u1)/
a1 = (Mece
– M1c1)/c1 = Me(Te/T1)1/2
– M1, which is all stuff you already have)
f.
What would the
Thrust Specific Fuel Consumption be?
(Note that TSFC = (Heat input)/Thrust*c1
= [
(CP(T3t
– T2t)c1]/[Thrust*c12]
= [(
c1)/Thrust]
[(g/(g‑1))R(T3t–T2t)/(gRT1)]
= [1/(Specific thrust)] [1/(g‑1)] [(T3t–T2t)/T1]
and you have everything needed to calculate T3t
and T2t)
g.
Can any fuel
generate enough heat to accomplish this?
Look at stoichiometric hydrogen-air and see if the heat release per unit
mass = fstoichQR is equal to or greater than the heat
input needed = CP(T3t – T2t). (Your answer should be NO, but support
with numbers).
Problem #2
LetÕs (sort of) repeat problem 1 c – f using
GASEQ, which you can download from http://www.gaseq.co.uk.
a.
Note
the enthalpy (h1) and sound speed (c1) of air at ambient
conditions (227 K, 0.0107 atm), then find the kinetic energy of the ambient air
u12/2= (c1M1)2/2. Then select process ÒAdiabatic
compression/expansionÓ (be sure to use air as the reactants, dissociated air as
the products, and uncheck the Òfrozen compositionÓ box). Compress the air to a product
temperature T2 of 3000K by adjusting your guess of P2
(should be around 300 atm) and hitting the ÒCalculateÓ button each time.
b.
Now
do the combustion. To do this, letÕs
first re-visit the constant-temperature heat addition analysis. The momentum equation is AdP +
du
= 0 or AdP +ruAdu = 0, and the energy equation is h + u2/2
= constant or dh + udu = 0.
Combining these, plus the ideal gas law P = rRT yields dP/P = dh/RT. T is constant by assumption, but R is
not quite constant since R = å/M and the molecular weight M will changed somewhat during
combustion. But if we take a value
of M averaged
between the reactant and product mixtures, we wonÕt be too far off. So if we assume constant (averaged) M and thus constant R, we obtain
ln(P3/P2) = (h3 –
h2)/RT2
where T2 = T3 = 3000K. So the process for doing the combustion
is:
1.
Choose
as reactants Òhydrogen-air flameÓ and as products ÒH2/O2/N2 products.Ó (Note that weÕve ignored any mixture
process and the effect that has on the mass flow, stagnation P and T,
etc.) The default mixture strength
is stoichiometric, so you shouldnÕt have to change that. Again be sure Òfrozen compositionÓ is
not checked.
2.
Guess
P3
3.
For
the problem type, choose ÒEquilibrium at defined T and PÓ, enter the 3000K for
T3 and your guess for P3, and hit Òcalculate.Ó
4.
Get
h2 and M2, h3 and M3 from GASEQ, calculate the
average molecular weight = Mavg = (M2 + M3)/2, and calculate the average R
= å/Mavg.
5.
Is the above equation ln(P3/P2) =
(h3 – h2)/RT2, satisfied? If not, adjust your guess for P3
and go back to step 3.
c.
Now
do the expansion. Select problem
type ÒAdiabatic compression/expansion.Ó
Hit ÒR << PÓ to transfer the products to reactants. Make sure the Òfrozen compositionÓ box
is unchecked. You should be able
to choose a product pressure of 0.01 atm but this doesnÕt converge. Instead choose a product pressure of
0.1 atm, hit ÒCalculate,Ó then hit ÒR << PÓ to transfer the products to
reactants, check the Òfrozen compositionÓ box, choose a product pressure of
0.0107 atm, hit ÒCalculateÓ one more time and youÕre done. Note the final enthalpy he.
d.
Compute
the product velocity from h1 + u12/2 = he
+ ue2/2. You
have everything except ue.
Note that GASEQ gives you enthalpies in kJ/kg, not J/kg, so you need to
multiply GASEQÕs values of h by 1000 to get the units right. You now have fair warning, I will not
be very forgiving if youÕre numbers are off by (1000)1/2!!!
e.
Compute
the specific thrust = (ue – u1)/c1,
which should be a lot lower than in problem 1 because your answer to 1g was NO.
f.
Compute
TSFC = (Heat input)/Thrust*c1 =
c1fstoichQR/(
(ue
– u1)*c12) = (1/(Specific thrust)) fstoichQR/c12. This should be pretty similar to your
answer to problem 1. Also
calculate the Specific Impulse = (1/TSFC)(QR/c1gearth). I get about 2100 seconds, much better
than the best H2-O2 rocket engines (about 450 sec) but
not that great considering how hard it will be to get anywhere near this ideal
performance.
Problem #3
Estimate
the zero Mach number thrust of a Pulse Detonation Engine using propane in the
following way.
a.
Estimate
the dimensionless heat addition H for stoichiometric propane-air assuming T1
= 300K and P1 = 1 atm.
b.
Compute
the detonation Mach number M1 assuming g = 1.4, and the incoming reactant
velocity u1 = M1c1
c.
Compute
the post-shock Mach number M2, temperature T2 and
pressure P2 using the analytical formulas (the ones with all the MÕs
and gÕs flying
around) given in Lecture 13.
d.
Compute
the pressure P3, temperature T3, and sound speed c3
after heat addition to M3 = 1 in a constant-area duct.
e.
WeÕve
computed the velocity of the products in the frame of reference attached to the
moving detonation front. We need
the velocity in the frame of reference of the unburned gas, i.e. in the
laboratory frame of reference. So
compute u3 (lab frame) = u1 – u3 = u1
– c3M3 = u1 – c3.
f.
The
gas behind the detonation products is moving toward the open end of the tube
with a velocity u3,lab.
But the velocity of the gas at the closed end of the tube must be
zero. Thus, the detonation
products act like a piston and cause an expansion wave in the products. Compute the pressure P4,
temperature T4 and sound speed c4 of the gas after this
expansion wave according to the isentropic wave relations from 1D gas dynamics:
![]()
where Du = u3,lab – u4,lab
= u3,lab – 0 = u3,lab.
g.
Now
compute the specific impulse. If we
assume, as discussed in class, that the approximate time the thrust surface ÒfeelsÓ
the pressure P4 is L/u1 + L/c4, where L is the
tube length, then the total impulse is (P4 – P1)AL(1/u1
+ 1/c4), where A is the tube (and thrust surface) cross-sectional area. Then the specific impulse = (total
impulse)/(fuel weight), where the fuel weight is (total mass)(fuel mass
fraction)g = (r1)(volume)fg = r1ALfg = (P1/RT1)ALfg. And finally recall that the specific heat addition H from
part (a) is given by H = fQR/RT1, so the fuel weight is (P1/RT1)AL(HRT1/QR)g
= P1ALHg/QR.
Thus the specific impulse is

h.
Compute
the specific thrust and TSFC.
Problem #4
Now
use GASEQ again, which conveniently offers a CJ detonation solver.
a.
Choose
reactants Òpropane-air flameÓ and products ÒHC/O2/N2 products.Ó (Again the default mixture strength is
stoichiometric, so you shouldnÕt have to change that.) Use 300K and 1 atm as the initial
conditions. Choose Problem type ÒC-J-DetonationÓ
and hit ÒCalculate.Ó Note the
incoming reactant velocity u1 = c1M1 and the
sound speed (c3) and specific heat ratio (g3) of the
products. Note that M3
= 1 as required for a CJ detonation.
Compute u3,lab = u1 – u3 = u1
– c3M3 = u1 – c3.
b.
Estimate
the final pressure P4 after the expansion wave from the relation
![]()
which is not strictly valid since g is not constant between states 3
and 4 when we consider gases with non-constant specific heats and dissociation,
g
changes so little during this process weÕll neglect that.
c.
Now
hit ÒR << PÓ to transfer the products to reactants, select process Òadiabatic
compression/expansion,Ó select product pressure P4, and hit ÒCalculate.Ó Note the sound speed (c4) of
the expanded products.
![]()
d.
Compute
the specific thrust, TSFC and specific impulse in the usual way. I get ISP between 1200 and
1400 seconds – not exactly spectacular.
Problem #5

Consider
a simple hypersonic propulsion system at an initial Mach number of 7 that
consists of:
Process 1: Heat addition at constant area from M =
7 to M = 3
Process 2: Isentropic expansion back to Pe
= Pa